Ordered Fields and the Least Upper Bound Axiom
Calculus is full of theorems that feel too obvious to
need proof. A continuous function that is negative at
one end of an interval and positive at the other must
vanish somewhere in between. An increasing sequence that
stays below some fixed number must settle down to a
limit. Both statements are false if
“number” means “rational number”. The polynomial
This chapter finds the one property that separates
the real numbers from the rationals: in
What you need. From Logic and
Proof, Chapter 1: proof by cases (Logic and Proof, Definition 1.6.1).
From Logic and Proof, Chapter 2: the
irrationality of
Time. About 30 hours on the core track (all of A, one B, and one C per section, the exit checks); about 45 hours for everything.
Roadmap
- Ordered fields and the gap in the
rationals. The axioms that
and share, the rules for inequalities they imply, and absolute value with the triangle inequality. - Upper bounds, maxima and suprema. The vocabulary for sets of numbers, and a proof that a bounded set of rationals can have no rational supremum.
- The least upper bound axiom. The
single assumption that distinguishes
from , and why infima then come free. - Working with the supremum. The
characterization of the supremum, sup approximation, and the rules for suprema of scaled sets and sums. - The Archimedean property. Where
sits in , and the Archimedean property: is not bounded above, which fails in some ordered fields. - Density of
and the existence of roots. A rational between any two reals, and (and every -th root) constructed as a supremum. - Nested intervals, and why
is uncountable. Shrinking closed intervals share a point, and no list contains every real number.
Named moves
- Split the supremum into its two
properties. To prove
, prove that is an upper bound, and then that it is the least one. - Sup approximation. “
is not an upper bound, so some exceeds it.” With this gives with . - Equality of suprema by two
inequalities. Prove
by exhibiting an upper bound, then prove with an , splitting the budget as when two sets are involved. - Construct a point as a supremum.
Define the set of points where “things are still fine”,
take its supremum, and rule out each way it could fail.
The existence of
is the first instance; the intermediate value theorem and the Heine–Borel theorem are proved the same way.